30v^2+144v-30=0

Solution for 30v^2+144v-30=0 equation:

30v^2+144v-30=0

a = 30; b = 144; c = -30;
Δ = b2-4ac
Δ = 1442-4·30·(-30)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-156}{2*30}=\frac{-300}{60}
=-5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+156}{2*30}=\frac{12}{60}
=1/5
$